4[3(x+1)]+1=2(-31-x)+2x+31

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Solution for 4[3(x+1)]+1=2(-31-x)+2x+31 equation:


Simplifying
4[3(x + 1)] + 1 = 2(-31 + -1x) + 2x + 31

Reorder the terms:
4[3(1 + x)] + 1 = 2(-31 + -1x) + 2x + 31
4[(1 * 3 + x * 3)] + 1 = 2(-31 + -1x) + 2x + 31
4[(3 + 3x)] + 1 = 2(-31 + -1x) + 2x + 31
[3 * 4 + 3x * 4] + 1 = 2(-31 + -1x) + 2x + 31
[12 + 12x] + 1 = 2(-31 + -1x) + 2x + 31

Reorder the terms:
12 + 1 + 12x = 2(-31 + -1x) + 2x + 31

Combine like terms: 12 + 1 = 13
13 + 12x = 2(-31 + -1x) + 2x + 31
13 + 12x = (-31 * 2 + -1x * 2) + 2x + 31
13 + 12x = (-62 + -2x) + 2x + 31

Reorder the terms:
13 + 12x = -62 + 31 + -2x + 2x

Combine like terms: -62 + 31 = -31
13 + 12x = -31 + -2x + 2x

Combine like terms: -2x + 2x = 0
13 + 12x = -31 + 0
13 + 12x = -31

Solving
13 + 12x = -31

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + -13 + 12x = -31 + -13

Combine like terms: 13 + -13 = 0
0 + 12x = -31 + -13
12x = -31 + -13

Combine like terms: -31 + -13 = -44
12x = -44

Divide each side by '12'.
x = -3.666666667

Simplifying
x = -3.666666667

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